dnl Process this file with autoconf to produce a configure script.
dnl
-dnl $Id: configure.in,v 1.79 2002/09/07 02:11:06 hal9 Exp $
+dnl $Id: configure.in,v 1.80 2002/09/26 18:47:46 hal9 Exp $
dnl
dnl Written by and Copyright (C) 2001, 2002 the SourceForge
dnl Privoxy team. http://www.privoxy.org/
dnl Temple Place - Suite 330, Boston, MA 02111-1307, USA.
dnl
dnl $Log: configure.in,v $
+dnl Revision 1.80 2002/09/26 18:47:46 hal9
+dnl This is most of Al's patch for --with-user and --with-group which tests that
+dnl these are valid values, if specified. If not specified, they are left empty.
+dnl
dnl Revision 1.79 2002/09/07 02:11:06 hal9
dnl Remove some testing stuff inadvertantly left in.
dnl
dnl AutoConf Initialization
dnl =================================================================
-AC_REVISION($Revision: 1.79 $)
+AC_REVISION($Revision: 1.80 $)
AC_INIT(src/jcc.c)
if test ! -f src/config.h.in; then
]
)
+dnl =================================================================
+dnl Check for user and group validity
+dnl =================================================================
+
+$ID privoxy >/dev/null 2>/dev/null
+if ! test $? -eq 0 ; then
+ AC_MSG_WARN(There is no user 'privoxy' on this system)
+fi
+AC_MSG_CHECKING([for user])
AC_ARG_WITH(user,
[ --with-user=privoxy Set user under which privoxy will run],
[
if test $ID = no ; then
AC_MSG_ERROR(There is no 'id' program on this system)
else
+ AC_MSG_RESULT($with_user)
$ID $with_user 2>/dev/null >/dev/null
if test $? -eq 0 ; then
USER=$with_user;
if test $ID = no ; then
AC_MSG_ERROR(There is no 'id' programm on this system)
else
- $ID privoxy >/dev/null
- if test $? -eq 0 ; then
- USER=privoxy;
- else
- AC_MSG_WARN(There is no user 'privoxy' on this system)
- USER=$with_user
- fi
+ AC_MSG_RESULT(none specified)
+ USER=$with_user
fi
]
)
AC_SUBST(USER)
+AC_MSG_CHECKING([for group])
AC_ARG_WITH(group,
[ --with-group=privoxy Set group for privoxy],
- [
+ [
if test "x$withval" != "xyes"; then
if test $BGROUPS = no ; then
AC_MSG_ERROR(There is no 'groups' program on this system)
else
+ AC_MSG_RESULT($with_group)
$BGROUPS $USER >/dev/null
if test $? -eq 0 ; then
# FIXME: this fails if valid group, but not first group
# listed.
- if test "$with_group" != "`$BGROUPS $USER 2>/dev/null |$AWK '{print $3}'`" ; then
+ if test "$with_group" != "`$BGROUPS $USER | sed 's/.*: //' 2>/dev/null |$AWK '{print $1}'`" ; then
AC_MSG_ERROR(The given value '$withval' does not match group entry)
else
GROUP=$with_group;
if test $BGROUPS = no ; then
AC_MSG_ERROR(There is no 'groups' programm on this system)
else
- $BGROUPS $USER >/dev/null
- if test $? -eq 0 ; then
- if test "$with_group" != "`$BGROUPS $USER 2>/dev/null |$AWK '{print $3}'`" -a "$with_group" != "" ; then
- AC_MSG_ERROR('$USER' isn't a member of '$with_group' group)
- else
- GROUP=$with_group;
- fi
- else
- AC_MSG_ERROR(There is no group entry for user '$USER')
- fi
+ AC_MSG_RESULT(none specified)
+ GROUP=$with_group;
fi
]
)